The TAKE FIVE winning numbers for Friday, March 17, 2006 were: 1, 6, 10, 34 and 38.

There were three first-prize winners who matched five numbers for $36,455.50 each. There were 297 second-prize cash winners who matched four numbers for $552.00 each; and 11,044 third-prize winners who matched three numbers for $24.50 each.

There were 131,253 winners of bonus Free Play tickets for matching two of the five winning numbers. Free Plays are "Quick Pick" tickets good for a subsequent TAKE FIVE drawing that must be collected within 45 days from a Lottery sales agent. The total number of winners was 142,597.

First prize of $36,455.50 will be paid to 3 winners.

There were a total of 11,344 cash winners.